Datediff giving output based on year...

Hi Everyone,
Whenever I am giving datediff(yy,'31 Dec 2003','1 Jan 2004') it is showing 1
as the result. But is it possible to get the difference in year purely base
d on date and not only on the Year part of the date?
For Example Difference between 26 June 2002 and 21 June 2004 should give me
1 instead of 2.
Thanx in advance for the help.
Regards,
Dipankar GangulyHi
Maybe something on the lines of:
DECLARE @.StartDate Datetime
DECLARE @.EndDate Datetime
SET @.StartDate = '20020626'
SET @.EndDate = '20040621'
SELECT MAX([NoYears])
FROM ( SELECT 1 as [NoYears] UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5 ) A
WHERE DATEADD(yy,[NoYears],@.StartDate) <= @.EndDate
John
"dipankarganguly" <dipankarganguly@.discussions.microsoft.com> wrote in
message news:46F7C4C3-74A1-4008-9688-C7AEEFB00F3B@.microsoft.com...
> Hi Everyone,
> Whenever I am giving datediff(yy,'31 Dec 2003','1 Jan 2004') it is showing
1 as the result. But is it possible to get the difference in year purely
based on date and not only on the Year part of the date?
> For Example Difference between 26 June 2002 and 21 June 2004 should give
me 1 instead of 2.
> Thanx in advance for the help.
> Regards,
> Dipankar Ganguly|||Hi,
Thanx for the opinion. Actually I want to use the datediff function only wit
h Year parameter. And it won't be possible for me to know the year differenc
e as hardcoded in the solution.
Regards,
Dipankar Ganguly
"John Bell" wrote:

> Hi
> Maybe something on the lines of:
> DECLARE @.StartDate Datetime
> DECLARE @.EndDate Datetime
> SET @.StartDate = '20020626'
> SET @.EndDate = '20040621'
> SELECT MAX([NoYears])
> FROM ( SELECT 1 as [NoYears] UNION ALL
> SELECT 2 UNION ALL
> SELECT 3 UNION ALL
> SELECT 4 UNION ALL
> SELECT 5 ) A
> WHERE DATEADD(yy,[NoYears],@.StartDate) <= @.EndDate
> John
> "dipankarganguly" <dipankarganguly@.discussions.microsoft.com> wrote in
> message news:46F7C4C3-74A1-4008-9688-C7AEEFB00F3B@.microsoft.com...
> 1 as the result. But is it possible to get the difference in year purely
> based on date and not only on the Year part of the date?
> me 1 instead of 2.
>
>|||Hi
Datediff will not give you the number of full years. As detailed in books
online- Datediff returns the number of date and time boundaries crossed
between two specified dates.
Try using:
DECLARE @.StartDate Datetime
DECLARE @.EndDate Datetime
SET @.StartDate = '20020626'
SET @.EndDate = '20040621'
SELECT CASE WHEN MONTH(@.StartDate) > MONTH(@.EndDate) OR
(MONTH(@.StartDate) = MONTH(@.EndDate) AND DAY(@.StartDate) > DAY(@.EndDate) )
THEN YEAR(@.EndDate)-YEAR(@.StartDate) - 1
ELSE YEAR(@.EndDate)-YEAR(@.StartDate)
END AS Years
John
"dipankarganguly@.hotmail.com"
<dipankarganguly@.hotmail.com@.discussions.microsoft.com> wrote in message
news:BD2D3724-0BD4-4E9A-B69A-C9B272AF9332@.microsoft.com...
> Hi,
> Thanx for the opinion. Actually I want to use the datediff function only
with Year parameter. And it won't be possible for me to know the year
difference as hardcoded in the solution.[vbcol=seagreen]
> Regards,
> Dipankar Ganguly
> "John Bell" wrote:
>
showing[vbcol=seagreen]
give[vbcol=seagreen]|||So what are you trying to accomplish? Could you post the DDL of the table or
tables you are querying?
Andrew C. Madsen
Information Architect
Harley-Davidson Motor Company
"dipankarganguly" <dipankarganguly@.discussions.microsoft.com> wrote in
message news:46F7C4C3-74A1-4008-9688-C7AEEFB00F3B@.microsoft.com...
> Hi Everyone,
> Whenever I am giving datediff(yy,'31 Dec 2003','1 Jan 2004') it is showing
1 as the result. But is it possible to get the difference in year purely
based on date and not only on the Year part of the date?
> For Example Difference between 26 June 2002 and 21 June 2004 should give
me 1 instead of 2.
> Thanx in advance for the help.
> Regards,
> Dipankar Ganguly